Python Program for Leap year
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Created By: asad_fazlani Created at: 08-31-2021
Tags: python leap year using python
We add a Leap Day on February 29, almost every four years. The leap day is an extra, or intercalary day and we add it to the shortest month of the year, February.
In the Gregorian calendar three criteria must be taken into account to identify leap years:
In the Gregorian calendar three criteria must be taken into account to identify leap years:
- The year can be evenly divided by 4, is a leap year, unless:
- The year can be evenly divided by 100, it is NOT a leap year, unless:
- The year is also evenly divisible by 400. Then it is a leap year.
- The year can be evenly divided by 100, it is NOT a leap year, unless:
This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years
Task
You are given the year, and you have to write a function to check if the year is leap or not.
You are given the year, and you have to write a function to check if the year is leap or not.
Note that you have to complete the function and remaining code is given as template.
Output Format
Output is taken care of by the template. Your function must return a boolean value (True/False)
Sample Input : 1990
Sample output : False
program :
def is_leap(year):
if year%4 ==0 and year%100 != 0:
return True
elif year%400 ==0:
return True
elif year%100 == 0:
return False
else:
return False
year = int(input())
print(is_leap(year))
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